Q : Write a function that returns 1 if the two matrices passed to it as argument are equal and 0
otherwise.
Solution :
#include<stdio.h>
#include<conio.h>
#define ROW 2
#define COL 2
int
compare(int a1[ROW][COL],int a2[ROW][COL]);
void main()
{
int
ar1[ROW][COL],ar2[ROW][COL],r,c;
clrscr();
printf("\nFirst Array
Input\n");
for(r=0;r<ROW;r++)
{
for(c=0;c<COL;c++)
{
printf("Enter
Number>> ");
scanf("%d",&ar1[r][c]);
}
}
printf("\nSecond Array
Input\n");
for(r=0;r<ROW;r++)
{
for(c=0;c<COL;c++)
{
printf("Enter
Number>> ");
scanf("%d",&ar2[r][c]);
}
}
if(compare(ar1,ar2)==1)
printf("\nIdentical");
else
printf("\nNot
Identical");
getch();
}
int
compare(int a1[ROW][COL],int a2[ROW][COL])
{
int r,c,flag=1;
for(r=0;r<ROW;r++)
{
for(c=0;c<COL;c++)
{
if(a1[r][c]!=a2[r][c])
{
flag=0;
break;
}
}
if(flag==0)
break;
}
if(r==ROW)
return 1;
else
return 0;
}
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